转换为字符串并反转
num = 12345reversed_num = int(str(num)[::-1])print(reversed_num) 输出:54321
使用while循环
num = 12345reversed_num = 0while num > 0:reversed_num = reversed_num * 10 + num % 10num = num // 10print(reversed_num) 输出:54321
使用递归
def reverse_num(num):if num == 0:return 0else:return reverse_num(num // 10) * 10 + num % 10print(reverse_num(12345)) 输出:54321

使用reduce和lambda函数
from functools import reducenum = 12345reversed_num = reduce(lambda x, y: y + x, map(int, str(num)))print(reversed_num) 输出:54321
处理32位有符号整数
def reverse(x: int) -> int:res = abs(x)boundry = 1 << 31while res != 0:res = res * 10 + res % 10if res > boundry:return 0return res if x >= 0 else -resprint(reverse()) 输出:0(超出32位有符号整数范围)
以上方法均可实现数字的反转。选择哪种方法取决于你的具体需求和对代码简洁性的考虑
